5d^2-12d+7=0

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Solution for 5d^2-12d+7=0 equation: 



5d^2-12d+7=0

a = 5; b = -12; c = +7;
Δ = b2-4ac
Δ = -122-4·5·7
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2}{2*5}=\frac{10}{10}
=1
$


$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2}{2*5}=\frac{14}{10}
=1+2/5
$

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